Re: invalid use of template-name 'Array' without an argument(compile error, plz help)

eric <>
Sat, 11 Jun 2011 02:50:13 -0700 (PDT)
On Jun 11, 1:24 am, "io_x" <a...@b.c.invalid> wrote:

"io_x" <a...@b.c.invalid> ha scritto nel messaggionews:4df3235c$0$13976$4=

2 try; some error found, don't know if it compile

3 try, there is no 2 without 3

#include <stdint.h>
#include <stdlib.h>
#define u32 uint32_t
#define u8 uint8_t

template < class elemType >
class Array {
  // parameterize element type
  Array(u32 size = 0)
     {ia_=0; size_=-1;}
   else if(size==0)
     {ia_=0; size_= 0;}
   else {u32 i;
         size_=-1; ia_=0;
         if(sizeof(elemType)>0xFFF) return;
         ia_=(elemType*) malloc(size* sizeof(elemType));
 cout << (void*)ia_;
 cout << " here in Array() elementsz= " << sizeof(elemType) << "\n";
         if(ia_==0) return;
         for(i=0; i<size_; ++i)

  elemType& operator[](u32 index){ return ia_[index]; }

  Array(Array& rhs )
        {size_=-1; ia_=0; return;}
   else {u32 i;
         size_=-1; ia_=0;
         if(rhs.size_>0xFFFF) return;
         if(sizeof(*(rhs.ia_)) > 0xFFF) return;
         ia_=(elemType*) malloc(rhs.size_ * sizeof(elemType))=


         cout << (void*)ia_;
         cout << " sizeelm==" << sizeof(elemType) << "\n";
         if(ia_==0) return;
         for(i=0; i<size_; ++i)

 ~Array(){ cout << "~" << (void*)ia_ << "\n"; free(ia_);}

  u32 operator==(Array& a)
  {u32 i;
             return 0;
             return 0;
   for(i=0; i<size_; ++i)
     {if(a[i]!=*this[i]) return 0;
   return 1;

  u32 operator!=(Array& a){return !(*this==a)}

  u32 size(void){return size_; }

  u32 size_;
  elemType* ia_;


#include <iostream.h>

int main(void)
{u32 array_size=4;
 u32 ix;
 Array<u32> ia(array_size); // elemType becomes u32
 Array<double> da(array_size); // elemType becomes double
 Array<char> ca(array_size); // elemType becomes char
 Array<u32> iia(ia);



     {cout << "Errore memoria insufficiente\n";
      return 0;

 for(ix=0; ix<array_size; ++ix )
    da[ix]=ix * 1.75;
    ca[ix]=ix + 'a';

 for(ix=0; ix<array_size; ++ix )
     std::cout << "[ " << ix << " ] ia: " << ia[ix]
               << "\tca: " << ca[ix]
               << "\tda: " << da[ix] << "\n";
 return 0;


Dear io_x: Thanks your code/effor/help(and hint in your mixing c/c++
code), I cut and paste (and little bit modify), it compile and run in
my system and it also give me a lot encourage to improve/fix my own c+
+ code to work. THANKS, Eric

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