Re: Problem with template
I have a derived template class and I want to call a method of the
derived class from the base class.
But the method need a template parameter.
How can I do?
Make the base class a template as well, and make that function a pure
virtual function which every derived class must override.
Here is the code that doesn't work.
using namespace std;
std::cout << "constructeur de A" << std::endl;
std::cout << "destructeur de A" << std::endl;
virtual void setValue(T) = 0;
template <class T> class B: public A
std::cout << "constructeur de B" << std::endl;
std::cout << "destructeur de B" << std::endl;
void setValue(T p_value)
_value = p_value;
A *a = new B<int>;
If the destructor of A isn't virtual, the deletion of 'a' pointer will
have undefined behaviour.
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