Re: Conversion of pointer-to-member
On Jul 26, 9:20 pm, Frank Birbacher <bloodymir.c...@gmx.net> wrote:
Hi!
I wonder why pointers to members seem so limited to me. I tried to do
the following:
struct Base {
virtual void doBar() =0;
};
template<typename T>
struct Dev : Base {
void doBar();
};
struct Test {
Dev<int> i;
Dev<float> f;
};
int main() {
Base Test::* const pt = &Test::i; //ERROR here
I'm not sure what you're trying to do here. "Test" is a definition,
not an actual object. You can't get a pointer to a member of a class
if there is no object of that type.
Test t;
(t.*pt).dobar();
}
It results in an error: a value of type "Dev<int> Test::*" cannot be
used to initialize an entity of type "Base Test::*const".
Well, sure there is an Instance of Base in every object of type Test.
Can I have a pointer-to-member to it?
Frank
You can get a pointer to the member if you define the pointer to an
actual object.
Here's your program modified to compile. Without knowing your actual
intend, I can't be sure that's what you want however.
struct Base {
virtual void doBar() =0;
};
template<typename T>
struct Dev : Base {
void doBar() {};
};
struct Test {
Dev<int> i;
};
int main() {
Test t;
Base* pt = &t.i;
pt->doBar();
}
Cheers,
Andre
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