Re: Multiply inherit from classes with conflicting function names
Adam wrote:
I have an unfortunate case where a single class wants to derive
from two
existing classes:
struct A { virtual long fun() = 0; };
struct B { virtual bool fun() = 0; };
struct Unfortunate : public A, public B { ??? };
Is it possible to fill in the ??? here with legal code?
I need two different function bodies; A::fun and B::fun do unrelated
things.
Yes, you need an intermediate class here.
struct A_tag {} const a_tag = {};
struct B_tag {} const b_tag = {};
// zero overhead shim
template<class derived>
struct A_shim : A
{
long fun() { return static_cast<derived*>(this)->fun(a_tag); }
};
// virtual call overhead shim
struct B_shim : B
{
bool fun() { this->fun(b_tag); }
virtual bool fun(B_tag) = 0;
};
struct fortunate : A_shim<fortunate>, B_shim
{
long fun(A_tag);
bool fun(B_tag);
};
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