Re: Exception throwing and guarentees about execution order

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 1 Feb 2009 06:32:56 -0800 (PST)
Message-ID:
<3880dcfe-fc6a-4e83-8df8-39a33b7e1c28@x16g2000prn.googlegroups.com>
On 1 f=E9v, 10:12, "Dick Brown" <inva...@invalid.invalid> wrote:

As far as I understand 11.6 (6) of the Ada 95 Reference
Manual, Ada implementations may "lose" information, where
exactly an exception has been raised. I'm not sure whether I
understand Ada in that regard, but that's off-topic anyways
(if someone wants to correct me there, I'd be grateful
nonetheless).

Something like:

try
{
  int i = 0;
  if (...) throw(i);
  int i = 1;
  if (...) throw(i);
  int i = 2;
}
catch (...)
{
  // i may be 0 or 1 or 2, no matter which throw(i) has brought us here
}

Now the real question: Does C++ have any similar provisions?
I've found nothing in the standard, am I right there?


It's hard to say. The above won't compile in C++, so we can't
begin to speak about the behavior it might have. If you change
it to:

    int i ;
    try {
        i = 0 ;
        if ( ... ) throw i ;
        i = 1 ;
        if ( ... ) throw i ;
        i = 2 ;
    } catch ( ... ) {
    }

Then in the catch block, i will have a value of 0 if the first
throw occurred, and a value of 1 if the second occurred. (I'm
not sure about Ada, but I imagine that a lot of languages don't
offer this guarantee---it has a decidedly negative impact on
optimization.)

--
James Kanze

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