From:

"osmium" <r124c4u102@comcast.net>

Newsgroups:

comp.lang.c++

Date:

Sun, 11 Feb 2007 06:26:08 -0800

Message-ID:

<538nc0F1rhbipU1@mid.individual.net>

I've been working on this code for about 2 days now, and can't get it

to work. Ultimately I need a algorithm to loop between my pieces of

validation code so that a variable meets 3 different conditions.

What I have is three while loops, example:

cout << "Please enter the number of judges: ";

/*

The reason that there are two variables for the number of judges,

is because I need to find out if the user entered a floating point

value. You shouldn't have 3.5 judges, as the for loop which counts

the scores later on will never be able to reach the end condition.

What is happening is that I get floating point value of the number

of judges (num_judges_float). If the user entered an integer eg: 4,

and if you put that value into an integer variable (num_judges_int),

you just get 4. So if you minus the floating point value of judges

from the number of judges in the integer variable, you should yield

zero. Anything else means the user did not enter a integer so a while

loop traps the error.

*/

cin >> num_judges_float;

num_judges_int = num_judges_float;

while((num_judges_float - num_judges_int) > 0)

{

cout << "\nError: You entered the number of judges with a

decimal point.\n\n";

cout << "Please enter the number of judges with no decimal

point: ";

cin >> num_judges_float;

num_judges_int = num_judges_float;

header();

}

// The header() function is called whenever input is given by the

// user. This produces the affect of keeping the text banner at the

// top of the console window the whole time.

header();

while(num_judges_int < 1)

{

// can't have negative judges or zero judges!

cout << "Error: The number of judges cannot be negative or

zero : ";

cout << "\n\nPlease reenter the number of judges : ";

cin >> num_judges_int;

header();

}

while(num_judges_int < 3)

{

/*

We aren't able to compute an average in the case that the number

of judges is 1 or 2. This is because later in this program

we have

to take the highest and lowest scores from the total of

scores.

If we do this we have to divide the remaining total by the

number

of judges minus two to get an average.(two for the two

scores we're

getting rid of). In the case we have two judges, we would wind up

dividing the total into zero (impossible) or in the case that we

had only one judge, we would be dividing the total into a

negative

number which would then give a negative result. As these events

don't lead to an average, it seemed best to me to give the user

an error message to explain what was wrong.

*/

cout << "Sorry, this program cannot give an average if there

is less than three judges";

cout << "\n\nPlease reenter the number of judges : ";

cin >> num_judges_int;

header();

}

to work. Ultimately I need a algorithm to loop between my pieces of

validation code so that a variable meets 3 different conditions.

What I have is three while loops, example:

cout << "Please enter the number of judges: ";

/*

The reason that there are two variables for the number of judges,

is because I need to find out if the user entered a floating point

value. You shouldn't have 3.5 judges, as the for loop which counts

the scores later on will never be able to reach the end condition.

What is happening is that I get floating point value of the number

of judges (num_judges_float). If the user entered an integer eg: 4,

and if you put that value into an integer variable (num_judges_int),

you just get 4. So if you minus the floating point value of judges

from the number of judges in the integer variable, you should yield

zero. Anything else means the user did not enter a integer so a while

loop traps the error.

*/

cin >> num_judges_float;

num_judges_int = num_judges_float;

while((num_judges_float - num_judges_int) > 0)

{

cout << "\nError: You entered the number of judges with a

decimal point.\n\n";

cout << "Please enter the number of judges with no decimal

point: ";

cin >> num_judges_float;

num_judges_int = num_judges_float;

header();

}

// The header() function is called whenever input is given by the

// user. This produces the affect of keeping the text banner at the

// top of the console window the whole time.

header();

while(num_judges_int < 1)

{

// can't have negative judges or zero judges!

cout << "Error: The number of judges cannot be negative or

zero : ";

cout << "\n\nPlease reenter the number of judges : ";

cin >> num_judges_int;

header();

}

while(num_judges_int < 3)

{

/*

We aren't able to compute an average in the case that the number

of judges is 1 or 2. This is because later in this program

we have

to take the highest and lowest scores from the total of

scores.

If we do this we have to divide the remaining total by the

number

of judges minus two to get an average.(two for the two

scores we're

getting rid of). In the case we have two judges, we would wind up

dividing the total into zero (impossible) or in the case that we

had only one judge, we would be dividing the total into a

negative

number which would then give a negative result. As these events

don't lead to an average, it seemed best to me to give the user

an error message to explain what was wrong.

*/

cout << "Sorry, this program cannot give an average if there

is less than three judges";

cout << "\n\nPlease reenter the number of judges : ";

cin >> num_judges_int;

header();

}

I suggest rewriting so you have a function that gets one satisfactory number

and returns it. Call this function three times from main. A satisfactory

number is a positive integer, but you have divided the responsibility into

two parts and the input must meet both criteria. Since the while loops are

disjoint in your code, problems seem likely.

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