Re: Multiple inheritance and pointer equivalence

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Thu, 19 Nov 2009 23:15:48 +0100
Message-ID:
<he4g2n$8qq$1@news.eternal-september.org>
* Juha Nieminen:

Alf P. Steinbach wrote:

So,
since they have virtual members you can just do dynamic_cast<void*>(a)
== dynamic_cast<void*>(b). :-)


  Why would that work? How can you even dynamic-cast to void*? What
would that even *mean*?


It gives you the address of the most derived object[1].

You can do it because the Holy Standard says so.

And that also formally answers why it would work, but the in-practice answer for
that also involves "because if you're using a compiler like MSVC then you have
provided the options that make it mostly standard-compliant, in particular
turning on RTTI support".

  Anyways, it's much easier to do it like:

    if(a == dynamic_cast<A*>(b)) ...


I find the simple downcasts more clear, and the cross-cast a bit challenging.

And apart from clarity, there is the academic problem that the cross-cast may
not be valid, e.g. in the case where a C contains two or more A sub-objects.

So I just provided the way that I found most clear, and guaranteed to work. :-)

Cheers & hth.,

- Alf

Notes:
[1] The special case casts in C++ include dynamic_cast<void*>, C style cast to
otherwise inaccessible base, reinterpret_cast to/from first data member of a
POD, and reinterpret_cast<char&> (he he...) to obtain address of object of silly
class that redefines address operator, but although the latter works in practice
  I think that for non-POD it's formally UB or implementation defined behavior?

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