Re: A toy example of embedding C code in lisp and vice versa

From:
nanothermite911fbibustards <nanothermite911fbibustards@gmail.com>
Newsgroups:
gnu.emacs.help,comp.lang.c,comp.lang.lisp,comp.lang.scheme,comp.lang.c++
Date:
Sun, 13 Jun 2010 14:40:20 -0700 (PDT)
Message-ID:
<745be699-9200-43c9-abfb-494944bfa5b6@h13g2000yqm.googlegroups.com>
On Jun 12, 12:08 pm, bolega <gnuist...@gmail.com> wrote:

Here is a link to a thread that discusses this topic but there is no
complete example.

http://objectmix.com/lisp/362409-howto-use-lisp-scripting-language-wi...

Lars Lune has a good section on code by searching this string

"On Tue, 18 Mar 2008 01:16:00 -0700, Blackguester wrote:"

but his code is replaced with smileys and even source shows it. I
could not muster the confidence as a newbie to go into it by myself.
Unless a guru can guide and explain.

http://common-lisp.net/project/cffi/http://common-lisp.net/project/cffi/m=

anual/html_node/Tutorial.htmlhttp://www.sbcl.org/manual/Foreign-Function-In=
terface.html

Should I pick SBCL or ECL ? I have a long term view.


8.8 Step-By-Step Example of the Foreign Function Interface

This section presents a complete example of an interface to a somewhat
complicated C function.

Suppose you have the following C function which you want to be able to
call from Lisp in the file test.c

     struct c_struct
     {
       int x;
       char *s;
     };

     struct c_struct *c_function (i, s, r, a)
         int i;
         char *s;
         struct c_struct *r;
         int a[10];
     {
       int j;
       struct c_struct *r2;

       printf("i = %d\n", i);
       printf("s = %s\n", s);
       printf("r->x = %d\n", r->x);
       printf("r->s = %s\n", r->s);
       for (j = 0; j < 10; j++) printf("a[%d] = %d.\n", j, a[j]);
       r2 = (struct c_struct *) malloc (sizeof(struct c_struct));
       r2->x = i + 5;
       r2->s = "a C string";
       return(r2);
     };

It is possible to call this C function from Lisp using the file
test.lisp containing

     (cl:defpackage "TEST-C-CALL" (:use "CL" "SB-ALIEN" "SB-C-CALL"))
     (cl:in-package "TEST-C-CALL")

     ;;; Define the record C-STRUCT in Lisp.
     (define-alien-type nil
         (struct c-struct
                 (x int)
                 (s c-string)))

     ;;; Define the Lisp function interface to the C routine. It
returns a
     ;;; pointer to a record of type C-STRUCT. It accepts four
parameters:
     ;;; I, an int; S, a pointer to a string; R, a pointer to a C-
STRUCT
     ;;; record; and A, a pointer to the array of 10 ints.
     ;;;
     ;;; The INLINE declaration eliminates some efficiency notes about
heap
     ;;; allocation of alien values.
     (declaim (inline c-function))
     (define-alien-routine c-function
         (* (struct c-struct))
       (i int)
       (s c-string)
       (r (* (struct c-struct)))
       (a (array int 10)))

     ;;; a function which sets up the parameters to the C function and
     ;;; actually calls it
     (defun call-cfun ()
       (with-alien ((ar (array int 10))
                    (c-struct (struct c-struct)))
         (dotimes (i 10) ; Fill array.
           (setf (deref ar i) i))
         (setf (slot c-struct 'x) 20)
         (setf (slot c-struct 's) "a Lisp string")

         (with-alien ((res (* (struct c-struct))
                           (c-function 5 "another Lisp string" (addr c-
struct) ar)))
           (format t "~&amp;back from C function~%")
           (multiple-value-prog1
               (values (slot res 'x)
                       (slot res 's))

             ;; Deallocate result. (after we are done referring to it:
             ;; "Pillage, *then* burn.")
             (free-alien res)))))

To execute the above example, it is necessary to compile the C
routine, e.g.: `cc -c test.c && ld -shared -o test.so test.o' (In
order to enable incremental loading with some linkers, you may need to
say `cc -G 0 -c test.c')

Once the C code has been compiled, you can start up Lisp and load it
in: `sbcl'. Lisp should start up with its normal prompt.

Within Lisp, compile the Lisp file. (This step can be done separately.
You don't have to recompile every time.) `(compile-file "test.lisp")'

Within Lisp, load the foreign object file to define the necessary
symbols: `(load-shared-object "test.so")'.

Now you can load the compiled Lisp (=93fasl=94) file into Lisp: `(load
"test.fasl")' And once the Lisp file is loaded, you can call the Lisp
routine that sets up the parameters and calls the C function: `(test-c-
call::call-cfun)'

The C routine should print the following information to standard
output:

     i = 5
     s = another Lisp string
     r->x = 20
     r->s = a Lisp string
     a[0] = 0.
     a[1] = 1.
     a[2] = 2.
     a[3] = 3.
     a[4] = 4.
     a[5] = 5.
     a[6] = 6.
     a[7] = 7.
     a[8] = 8.
     a[9] = 9.

After return from the C function, the Lisp wrapper function should
print the following output:

     back from C function

And upon return from the Lisp wrapper function, before the next prompt
is printed, the Lisp read-eval-print loop should print the following
return values:

     10
     "a C string"

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