Re: To retrieve Keys or values of a Map

From:
Alan Woodland <ajw@aberystwyth.ac.uk>
Newsgroups:
comp.lang.c++
Date:
Wed, 04 Nov 2009 12:05:38 +0000
Message-ID:
<d978s6xnca.ln2@news.aber.ac.uk>
Saeed Amrollahi wrote:

Dear all

I have a question. Is there any generic algorithm or solution to
access the keys or values
of a map? I frequently face to such problem and I usually write a
function to copy
the keys/values of a map into a container let say a vector.

Many thanks, in advance, for your help.


I've written a utility roughly like this:

#include <string>
#include <algorithm>
#include <iostream>
#include <list>
#include <map>
#include <iterator>

namespace {
   template <typename T1, typename T2>
   const T1& take_first(const typename std::map<T1,T2>::value_type& pair) {
     return pair.first;
   }
}

template <typename T1, typename T2>
std::list<T1> keys(const std::map<T1,T2>& in) {
   std::list<T1> klist(in.size());
   std::transform(in.begin(), in.end(), klist.begin(), take_first<T1,T2>);
   return klist;
}

int main() {
   std::map<std::string, int> map;
   map["test"] = 0;
   map["test2"] = 0;

   const std::list<std::string>& keys = ::keys(map);
   std::copy(keys.begin(), keys.end(),
std::ostream_iterator<std::string>(std::cout, "\n"));

   return 0;
}

Although this isn't exactly ideal, and would be a nice place to use a
lambda function in C++0x too.

There's a few annoying things about this though, the function take_first
has to live inside the anonymous namespace because it's not legal to
write the following, which given the absence of lambda functions would
be cleaner in my view:

template <typename T1, typename T2>
std::list<T1> keys(const std::map<T1,T2>& in) {
   struct {
     const T1& operator()(const typename std::map<T1,T2>::value_type&
pair) {
       return pair.first;
     }
   } take_first;

   std::list<T1> klist(in.size());
   std::transform(in.begin(), in.end(), klist.begin(), take_first);
   return klist;
}

I also never got type deduction for the function pointer argument to
std::transform to work, which I kind of expected it would, although
that's not exactly a problem.

Alan

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