Re: The following works in Linux

Maxim Yegorushkin <>
Wed, 3 Dec 2008 07:08:58 -0800 (PST)
On Dec 3, 12:34 pm, "" <>

#include <stdio.h>

struct _table_model_entry {
  struct _table_model_entry *next;
  int line_nr;
  int nr_fields;
  char *fields[0]; /* User defined */

int main(){
char * a,*b,*c,*d;
struct _table_model_entry tb;
tb.fields[0] = a;
tb.fields[1] = b;

But I dont get the use of an array size of 0 for member fields in the
struct _table_model_entry .

char *fields[0] is a gcc extension similar to C99 flexible array
member. You can find more information here:

The storage for that member must be allocated manually. It is normally
used with dynamic allocation:

    #include <stdlib.h>

    struct _table_model_entry {
      struct _table_model_entry *next;
      int line_nr;
      int nr_fields;
      char *fields[0]; /* User defined */

    typedef struct _table_model_entry tme;

    tme* tme_alloc(int fields_count)
        return (tme*)malloc(
              /* space for tme::fields member*/
            + sizeof(char*) * fields_count

    int main()
        tme* p = tme_alloc(2);
        p->fields[0] = NULL;
        p->fields[1] = NULL;


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