Re: Searching a vector with functionals

Jiri Palecek <>
Fri, 2 Nov 2007 20:30:30 CST
Matthias Buelow wrote:

I'm trying to implement a functor find_if, which takes a predicate,
searches a container (for example, vector) and returns (a reference
the first element for which the predicate function returns true. I
get it to work. Maybe someone can give me a hint? From my
the call and the template-generated functions do match, typewise. The
problem appears to be that main()::f does not satisfy
std::unary_function<element_t&, bool>& but I don't understand why.

f() is a temporary, which cannot bind to a reference, but only a const

gcc (GCC) 4.1.2 20061115 (prerelease) (Debian 4.1.1-21) gives me the
following error message: In function 'int main()': error: no matching function for call to
'find_if(std::vector<foo, std::allocator<foo> >&, main()::f, foo&)' note: candidates are: element_t& find_if(container_t&,
std::unary_function<element_t&, bool>&, element_t&) [with
container_t =
std::vector<foo, std::allocator<foo> >, element_t = foo]

from the following code:


using namespace std;

#include <functional>
#include <vector>

template<class container_t, typename element_t>
element_t &find_if(container_t &cont, unary_function<element_t &,
&fun, element_t &notfound)

[ snip ]


struct foo { int a; foo(int aa = 0): a(aa) {}; };

int main()
struct f: public unary_function<foo &, bool> {
bool operator()(foo &x) {

[ snip ]


vector<foo> fv;
foo notfound;

foo &x = find_if(fv, f(), notfound);

return 0;


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