Re: c_str from anonymous std::string

Andrew Tomazos <>
Tue, 13 Dec 2011 02:19:18 -0800 (PST)
On Dec 13, 12:39 am, "MikeWhy" <> wrote:

Goran wrote:

On Dec 12, 8:57 am, Andrew Tomazos <> wrote:

class X
operator std::string(); // stringify X instance


void f(const char*);

X x = ...

According to the C++11 standard, will the destructor of std::string
be called before or after the call to f, or is it undefined?

My understanding is that such temporaries is destroyed when statement
is finished, which, here, is after the semicolon.

It should be further noted that "string(x)" here is an explicit C-style
typecast, syntactically identical to "((std::string)x)", followed by copy
construction of std::string, creating not just one, but *two* temporary

$ cat < test.cpp

#include <iostream>

using namespace std;

class A
    A() { cout << "d"; }
    A(const A& a) : x(a.x) { cout << "c"; }

    int getx() const { return x; }
    int x;

class B
    B(int i) : x(i) {}
    operator A() { A a; a.x = x; return a; }

    int x;

void f(int x) { cout << x << endl; }

int main(int argc, char** argv)
    B b(argc);


$ g++ test.cpp
$ ./a.out

I only count one d. :)

Due to the return value optimization...

What a nasty bit of business. This isn't real code, is it? Just
some contrived nastiness to astonish and dismay job applicants?

Imagine how much less embarrassed you would be if you stated it this

    "I think that two temporaries will be created, won't they?"

and left it at that. ;)


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