Re: How make polymorphism optional?

From:
blargg.h4g@gishpuppy.com (blargg)
Newsgroups:
comp.lang.c++
Date:
Thu, 11 Sep 2008 09:49:48 -0500
Message-ID:
<blargg.h4g-1109080949480001@192.168.1.4>
In article
<01a57452-70dc-453c-b661-32ad77e4619d@k13g2000hse.googlegroups.com>,
Litvinov Sergey <slitvinov@gmail.com> wrote:

My problem is the following one. I have a huge number of objects of
base class: [...] And a derived class: [...]

Sometime I have no objects of Derived class and in those cases
I would like to get rid of polymorphism overhead. (speed is crucial
for me). It is OK for me to have a separate binary to handle those
cases. But the only design I came up with is with preprocessor to
"separate" virtual keyword in class definition

class Base {
#ifdefine NOPOLYMORPHISM
  void
method();
#else
  virtual void
method();
#endif
}

and the part of the program where the concrete type of the objects is
defined should be also modified.

Is there any better way to do that?


How about this? A forwarding function uses a boolean to decide whether to
call the virtual function normally, or with scope resolution in order to
make it a static call that can be inlined. Since it's a compile-time
constant, the selection is done during compilation; no preprocessor
necessary.

    // config.h

    bool const use_virtual = true;

    // Base.h

    class Base {
    public:
        void f();
    protected:
        virtual void vf();
    };

    inline void Base::f()
    {
        if ( use_virtual )
            vf();
        else
            Base::vf();
    }

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