Re: Reg. Function Templates

Jim Langston wrote:
:: "VSP" <abc@abc.com> wrote in message
:: news:f91fap$4a8$1@daniel-new.mch.sbs.de...
::: Hi,
:::
::: In the following code, we have created a template function,
::: We expected the output to display "A::A()" and "B::B()" but we
::: are getting both as "B::B()".
:::
::: class A
::: {
::: public:
::: A()
::: {
::: cout<<endl<<"A::A()";
::: }
::: };
:::
::: class B
::: {
::: public:
::: B()
::: {
::: cout<<endl<<"B::B()";
::: }
::: };
:::
::: template<class T>
::: void func()
::: {
::: T t;
::: }
:::
::: int main(int argc, char* argv[])
::: {
::: func<A>();
::: func<B>();
::: return 0;
::: }
:::
::: Please clarify.
::: Compiler Used: VC++ 6.0
::
:: In VC++ .net 2003 the output is the expected
::
:: A::A()
:: B::B()
::
:: Of course after I included <iostream> and changed cout and endl to
:: std::cout and std::endl.
::
:: Try a fresh build. If that doesn't work, it's a bug in VC++ 6.0.
:: 6.0 is fairly old, prestandard and has a few bugs. You definately
:: need to upgrade.

Yes, this is a known bug in VC6. The compiler uses function
parameters, but not template parameters, in the function signature.
This fools the linker into believing that there is only one func().

If you change the function to

template<class T>
void func(const T* = 0)
{
   T t;
}

it will work as it should.

If you try to learn C++, the free Visual C++ Express (VC8) is a much
better choice.

Bo Persson