Re: simple? sequence issue

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 6 Dec 2007 10:06:16 -0500
Message-ID:
<fj9359$hpb$1@news.datemas.de>
Christof Warlich wrote:

template<typename T> struct X {};
template<typename T, X<T> &x> struct Y1{};
class T;
template<X<T> &x, typename T> struct Y2{};
X<int> x;
Y1<int, x> y1;
Y2<x, int> y2; // this does not compile

Anyone who knows how to do it right?


When you try to instantiate Y2 template by giving it 'x' as the first
argument, the compiler has no idea what 'T' is in Y2. It cannot look
ahead to see that you've established that 'T' is 'int' in the second
argument. That's why instantiating 'Y1' works fine, since 'T' is
known at the time when it sees 'x', which then successfully matches
to the object of type X<int>.


And there is nothing like some forward declaration to tell the
compiler? As I said, I need _this_ sequence of template parameters
because I'd like to supply a default argument for T, e.g.:

template<X<T> &x, typename T = int> struct Y2{};
Y2<x> y2;

Or is there some other way to to provide this default argument?


You will likely have to define a different template for that and if
you need to share functionality, derive it from the Y2:

    template<X<int> &x> struct Y2int : Y2<int,X<int>&> {};

V
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