Re: Length of C++ arrays allocated by operator new[]

From:

Juha Nieminen <nospam@thanks.invalid>

Newsgroups:

comp.lang.c++

Date:

22 Aug 2011 06:06:42 GMT

Message-ID:

<4e51f1f2$0$2861$7b1e8fa0@news.nbl.fi>

Marcel M?ller <news.5.maazl@spamgourmet.org> wrote:

- STL causes the executable size to explode. One disadvantage of
template meta programming over generics.

  Why is this urban legend so persistent? People repeat it without actually
trying it.

  I just tested with these two programs:

//---------------------------------------------------------
int main()
{
    int* array = new int[10000];
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    delete[] array;
    return value;
}
//---------------------------------------------------------

//---------------------------------------------------------
#include <vector>

int main()
{
    std::vector<int> array(10000);
    for(int i = 0; i < 10000; ++i) array[i] = i;
    int value = 0;
    for(int i = 0; i < 10000; ++i) value += array[i];
    return value;
}
//---------------------------------------------------------

  The size of the first executable? 5104 bytes.
  The size of the second executable? 5528 bytes.

  Yeah, the size really exploded.