Re: Address of static method

"mlimber" <>
19 May 2006 13:01:52 -0700
Thorsten Kiefer wrote:

mlimber wrote:

Thorsten Kiefer wrote:

my compiler tells me that the address of a static method will always
evaluate to true (which is 1). Why that ? How can i get the address of a
static method ?
I'm using gcc3.

It should only evaluate to true if you are testing it. Otherwise it
should simply be a non-zero address. Please post a minimal but complete
sample of code that demonstrates the problem (cf.

Cheers! --M

thread.hpp :
#include <pthread.h>
#include <iostream>

namespace std {

class Thread {
                pthread_t pthread;

                static void *start_routine(void *x);
                static void test() {};

                        cout << &start_routine << endl;
                        cout << &test << endl;
                        int r = pthread_create(&pthread,0,start_routine,this);
                virtual int run() = 0;


threadtest.cpp :
#include <thread.hpp>
#include <iostream>

using namespace std;

class Thread1 : public Thread {
                int run() {
                        for(int i = 0;i < 10;++i)
                                cout << i << endl;

int main(int argc,char **argv){
        Thread1 t1;

Segmentation fault


This is neither a minimal nor a complete program -- the pthread
business is non-standard and unnecessary here to demonstrate your
problem, and you don't define Thread::start_routine() anywhere. Also,
you didn't tell us where the warning message was issued, but I checked,
and it's on each of the couts in Thread::Thread(). Before I get to
that, however, you may not add things to the std namespace, so get
Thread out of there. Anyway, it looks like that's a bug in g++ 3. It
doesn't happen on VC++ 6, 2003 (online), 2005, EDG (online) or Comeau
(online). Better ask in a gnu group. See this FAQ for some

Cheers! --M

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