Re: Will Modern C++ Design ever get fixed? Organization: unknown

From:
Andre Kaufmann <akfmnews@t-online.de>
Newsgroups:
comp.lang.c++.moderated
Date:
Fri, 8 Oct 2010 17:26:01 CST
Message-ID:
<i8nf0t$igg$00$1@news.t-online.com>
On 07.10.2010 19:53, Leigh Johnston wrote:

?"Leigh Johnston" <leigh@i42.co.uk> wrote in message
[...]

I tried to come up with a contrived example such as the one you give on


The code is only slightly different (have a look at the jump address)
it's hard to see the difference.
I used the following example (MSVC Windows) to check it:

volatile bool flag = false;

DWORD __stdcall SetIt(void* lpThreadParameter)
{
    flag = true;
    return 0;
}

int main(int argc, char* argv[])
{
    QueueUserWorkItem(&SetIt, 0, 0);
    while (!flag);
    printf("End");
    return 0;
}

The assembly code of [while(!flag)] is:

With volatile:

   00831020 mov al,byte ptr [aha (833370h)]
   00831025 test al,al
   00831027 je wmain+10h (831020h)

Without volatile:

   008F101F mov al,byte ptr [aha (8F3370h)]
    while (!aha);
   008F1024 test al,al
   008F1026 je wmain+14h (8F1024h)

In the example without volatile, the code jumps to

   008F1024 test al,al

and not to

   008F101F mov al,byte ptr [aha (8F3370h)]

Since the register is never changed (without volatile) it will be an endless
loop. Simply try to execute the code with and without volatile, you will see the
difference.

Andre

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