Re: Declaring members for Interfaces

Leonard Milcin <>
Thu, 01 May 2008 17:45:23 +0200
Wojtek wrote:

Todd wrote :

public enum NonOrdinal
    RADIUS( 21 ),
    DIAMETER( 42 );

     private double value;

     private NonOrdinal( double value )

        this.value = value;

    public double getValue()
        return value;

     public NonOrdinal getNonOrdinal(double value) throws
        for (NonOrdinal ord : NonOrdinal.values())
          if ( ord.getValue == value )
            return ord;

        throw new EnumNotFoundException("NonOrdinal not found: " + value);

OMG! I won't even comment. This is just silly... don't teach people if
you can't solve problems by yourself.

If you really, really need such a mechanism, try this:

public enum Test {

    A1( 1 ),
    A2( 2 );

    private final Integer value;

    private static final Map<Integer, Test> byValue;

    static {
        byValue = new HashMap<Integer,Test>();
        for (Test t : Test.values()) {
            byValue.put(t.value, t);

    private Test(Integer value) {
        this.value = value;

    private Integer getValue() {
        return value;

    public static Test getByValue(Integer value) {
        return byValue.get(value);



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