Re: Date parsing leniency

Tom Anderson <>
Fri, 16 Jan 2009 14:10:27 +0000
On Thu, 15 Jan 2009, Mark Space wrote:

Paul J. Lucas wrote:


    SimpleDateFormat df = "yyyy-MM-dd";
    df.setLenient( false );
    String s = "2007-02-04T10:45:21-08:00";
    Date d = df.parse( s );
    System.out.println( d );

I get:

    Sun Feb 04 00:00:00 PST 2007

I want it to parse the *whole* string successfully, or fail. How to I get
it to *not* succesfully parse the given string?

Just from reading the Java doc, I see that there are two calls that take
a ParsePosition object, which is updated to indicate the position the
parser stopped at. I suppose you could check if the ParsePosition was
the same as the length of the string.

This sounds like the right solution.

However, you could also consider a foetid hack:

private static final String SENTINEL = "!!!";

private static Date parseStrict(String dateStr, String pattern) throws ParseException {
  SimpleDateFormat df = new SimpleDateFormat(pattern + SENTINEL);
  return df.parse(dateStr + SENTINEL);


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