Re: URLConnection

"" <>
18 Oct 2006 22:50:12 -0700
This was helpfull, I have an idea how to do it now but I can't seem to
figure out how to specify the web page with out getting "unreported
exception; must be caught or declared to
be thrown" error

if i remove the URL line the program complies with out error

error -> URL url = new URL("");
        String user="", email="", pass="",body1="";
        user = UserText.getText();
        email = EmailText.getText();
        pass = PasswordText.getText();

        body1 = ("field1="+user+"&field2="+email+"&field3="+pass+"");
~~~~~~~going to call function~~~~~

static public String getURLPostString(URL url, String body) {
        StringBuffer sb = new StringBuffer();

    // find the newline character(s) on the current system
        String newline = null;
        try {
            newline = System.getProperty("line.separator");
        } catch (Exception e) {
            newline = "\n";

        try {
        // URL must use the http protocol!
            HttpURLConnection conn = (HttpURLConnection)
            conn.setAllowUserInteraction(false); // you may not ask the
            conn.setDoOutput(true); // we want to send things
            // the Content-type should be default, but we set it anyway
            conn.setRequestProperty( "Content-type",
"application/x-www-form-urlencoded" );
            // the content-length should not be necessary, but we're
            conn.setRequestProperty( "Content-length",

            // get the output stream to POST our form data
            OutputStream rawOutStream = conn.getOutputStream();
            PrintWriter pw = new PrintWriter(rawOutStream);

            pw.print(body); // here we "send" our body!

            // get the input stream for reading the reply
            // IMPORTANT! Your body will not get transmitted if you get
            // InputStream before completely writing out your output
            InputStream rawInStream = conn.getInputStream();

            // get response
            BufferedReader rdr = new BufferedReader(new
            String line;

            while ((line = rdr.readLine()) != null) {
            return sb.toString();
        } catch (Exception e) {
        System.out.println("Exception "+e.toString());
        return ""; // an exception occurred


Manish Pandit wrote:


You need to find out the login form fields for the site, as well as the
URL to post this form to. You also need to check if the site requires
cookie handling at the client. To start with, you can use the example
provided here:

It has an example of a form post and cookie-handling.


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