Re: Why declaring a private abstract method makes no sense??

From:
"Chris Uppal" <chris.uppal@metagnostic.REMOVE-THIS.org>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 8 Feb 2007 16:13:32 -0000
Message-ID:
<45cb4c6e$0$765$bed64819@news.gradwell.net>
Mark Thornton wrote:

A private member is visible only to the class that declares it.


It is also visible to nested/inner classes of the declaring class.


....and to any classes which enclose it.

But only in the sense that the compiler fakes access by generating non-private
backdoor access methods. That may be close enough for some purposes, but it
turns my stomach.

BTW, /inheritance/ as opposed to just /access/ is a different story. The
reader is invited to consider what the output of the following program should
be according to the spec, what it should be according to common-sense, and what
it will be according to the code generated by javac (I'm using JDK 1.6.0).

    -- chris

================
public class Test
{
    public static void
    main(String[] args)
    {
        Nested n = new Nested();
        n.test();

        Test t = new Nested();
        t.doIt();
    }

    private void
    doIt()
    {
        System.out.println("Doin' it");
    }

    public static class Nested
    extends Test
    {
        public void
        test()
        {
            this.doIt();
            super.doIt();
        }

        public void
        doIt()
        {
            System.out.println("Not gonna do it");
        }
    }
}
================

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