Re: Help with Java Calculator Program

From: (Stefan Ram)
27 Oct 2010 23:22:15 GMT
<> (Stefan Ram) writes:

On Oct 27, 9:37 am, (Stefan Ram) wrote:

for( counter.reset(); integers.hasNext(); )
if( integers.getNext().isGreaterThan( 9 ))counter.increment();

I'm having problems with that code working.

It assumes appropriate types of ?counter? and ?integers?.
Thus, the operations ?reset()?, ?hasNext()?, ?getNext()?,
?isGreaterThan( 9 )? and ?increment()? usually still need to
be implemented.

  Just for fun, here is a complete program with the above code
  in them method ?main?, except that ?getNext? was replaced by

public class Main
  static class Counter
  { int value;
    void reset(){ this.value = 0; }
    void increment(){ if( value >= ++value )
      throw new java.lang.RuntimeException(); }
    public final java.lang.String toString()
    { return java.lang.String.valueOf( value ); }}

  static class Integer
  { int value;
    public Integer( final int value ){ this.value = value; }
    public boolean isGreaterThan( final int value )
    { return this.value > value; }}

  static final Counter counter = new Counter();

  static final java.util.ArrayList<Integer> list =
  new java.util.ArrayList<Integer>();

  { list.add( new Integer( 1 ));
    list.add( new Integer( 11 ));
    list.add( new Integer( 11 ));

    ( new java.lang.Thread
      ( new java.lang.Runnable()
        { public void run()
          { java.lang.System.out.println( counter ); }})); }

  static final java.util.Iterator<Integer> integers = list.iterator();

  public static void main( final java.lang.String[] args )
    for( counter.reset(); integers.hasNext(); )
    if( 9 ))counter.increment(); }}

  It prints ?2? because in the list, there are 2 numbers
  greater than 9. Thus, it has counted the numbers greater
  than 9.

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