Re: Is clone a member function for array types?

Daniel Pitts <>
Mon, 03 Dec 2007 09:06:14 -0800
<> wrote:

According to the JLS clone is a public method for all array types:

6.4.5 Members of an Array Type

The public method clone, which overrides the method of the same name
in class Object and throws no checked exceptions. The return type of
the clone method of an array type T[] is T[].

However if I run the following program (JDK 1.5.0_04-b05 on Linux):

  import java.lang.reflect.*;
  public class Test {

    public static void main(String[] args) {
    int[] x = {1,2,3};

    Class cls = x.getClass();
    Method[] methods= cls.getMethods();
    for(Method meth: methods) {

I get the output

  Class:class [I
  Method:public native int java.lang.Object.hashCode()
  Method:public final native java.lang.Class
  Method:public final native void java.lang.Object.wait(long) throws
  Method:public final void java.lang.Object.wait(long,int) throws
  Method:public fina lean java.lang.Object.equals(java.lang.Object)
  Method:public final native void java.lang.Object.notify()
  Method:public final native void java.lang.Object.notifyAll()
  Method:public java.lang.String java.lang.Object.toString()

The clone method is missing.

The JavaDocs for the Class.getMethods is:

  Returns an array containing Method objects reflecting all the public
member methods of the class or interface represented by this Class
object, including those declared by the class or interface and those
inherited from superclasses and superinterfaces.

So I should have gotten all the public methods, and clone is supposed
to be public, but it's
not showing up.... Does anyone have any idea what I'm missing?

   Tom McGlynn

hmm... Try using getDeclaredMembers to see. It could be that array
cloning is a special case, look at the VM spec to see if there are any
hints there. Array types *are* a special case in the JVM.

Daniel Pitts' Tech Blog: <>

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