Re: System property user.dir

"MikeB" <>
1 Mar 2007 10:36:50 -0800
On Mar 1, 7:09 am, Lars Enderin <> wrote:

Kunkhmer skrev:

On Mar 1, 5:55 am, "MikeB" <> wrote:

in the Java API guide (
File.html) the docs mention a system property user.dir that supposedly
has the current user directory.

How do I access the value in this property?

Alternately, is there another way I can establish a base directory
such that, in a subdirectory of my package/jar, I can store data for
the application to read?

Eg. if my application is running in C:x\y\z, I'd like to have a
directory whose fully-qualified name is C:x\y\z\data. If the
application is transported and later runs on D:\a\b\c\, I'd like that
directory to resolve to D:\a\b\c\data.



user.dir : is where you program is starting from
to get the value, just write this line

String basedir = System.getProperty("user.dir");

in your case, basedir will be "D:\a\b\c"
you need to do something like: basedir + "\data" to get an absolute

To learn more, just run this small program.

/** start **/
import java.util.Enumeration;
import java.util.Properties;
public class Test {
   public static void main(String[] args) {
           Properties p = System.getProperties();
           Enumeration es = p.elements();
           while (es.hasMoreElements())
/** end **/

Smaller and better (also shows property names):

import java.util.Properties;
public class Props {
   public static void main(String[] args) {
     Properties p = System.getProperties();


Compile: javac
Run: java -cp . Props- Hide quoted text -

- Show quoted text -

Thanks for those sample programs. I was wondering how to look at all
the system properties.

I found that this line printed them all, not nicely formatted, but it
did the job.

    System.out.println("Properties: " + System.getProperties());

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