Re: find words that contains some specific letters

"John B. Matthews" <nospam@nospam.invalid>
Mon, 01 Jun 2009 07:38:22 -0400
In article
 Fralentino <> wrote:

On 1 Juni, 09:20, Andrew Thompson <> wrote:

On Jun 1, 4:16?pm, Fralentino <> wrote:

...I have a solution for this ..

What is your solution?

My solution:
boolean compareLetters(String toBeCompared,ArrayList<String> letters)

        for(int i = 0;i<toBeCompared.length();i++)
                return false;
        return true;


IIUC, you then have to run this method on every word in your dictionary.

Another approach is to permute the letters and search the dictionary.
A binary search of an ordered word list is O(log n), worst case.
Here's an example in Ada:


In Java, permutations can be checked quickly with the contains() method
of the Set interface, once the dictionary is read:

private static final String NAME = "/usr/share/dict/words";
private static final Set<String> set = new TreeSet<String>();
static {
    try {
        File file = new File(NAME);
        BufferedReader in = new BufferedReader(
            new InputStreamReader(new FileInputStream(file)));
        String s;
        while ((s = in.readLine()) != null) {
    } catch (IOException ex) {

Finding the permutations of a string in Java is straightforward:


John B. Matthews
trashgod at gmail dot com

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