Re: Question re testing constructor
Ian Shef <invalid@avoiding.spam> writes:
ram@zedat.fu-berlin.de (Stefan Ram) wrote in news:null-20111206201830
@ram.dialup.fu-berlin.de:
If the Java compiler is so smart at detecting null values,
why does he not also give an error on code like:
(( java.io.PrintStream )null ).println()
?
Short answer: Because the JLS says so. (see the third edition, paragraph
15.16 where it is explained that most casts are handled at run time).
Something similar:
It is difficult for me to forecast an ?unreachable statement? error.
For example, I would have expected such an error for
public class Main
{ public static void main( final java.lang.String[] args )
{ java.lang.System.out.println( "alpha3" );
if( true )return;
java.lang.System.out.println( "beta3" ); }}
, but did *not* get one, however, the compiler knows that the
beta3 statement *is* unreachable, because he does not care to
compile it.
Omitting the ?if( true )? will give an ?unreachable statement?
error.
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