Re: why Visual Studio can not optimize the initialization code?

=?Utf-8?B?R2Vvcmdl?= <>
Wed, 19 Dec 2007 06:26:02 -0800
Thanks Igor,

My question is almost answered. Finally, I want to confirm,

In the simple sample from MSDN,

it only saves the time of,

1. constructor of temporary object;
2. destructor of temporary object;

And it can not save time of the assignment operator. :-)

#include <stdio.h>
class RVO
            RVO(){printf("I am in constructor\n");}
            RVO (const RVO& c_RVO) {printf ("I am in copy constructor\n");}
            ~RVO(){printf ("I am in destructor\n");}
            int mem_var;
RVO MyMethod (int i)
            RVO rvo;
            rvo.mem_var = i;
            return (rvo);
int main()
            RVO rvo;


"Igor Tandetnik" wrote:

"George" <> wrote in message

I think NRVO could only optimize in the case of return value from a
function. From the name -- Named Return Value Optimization (NRVO), it
seems that only return value from a function could be optimized.

Yes, RVO (whether Named or otherwise) only applies to function return
With best wishes,
    Igor Tandetnik

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