Re: how to find whether it is released or not

From:
"Tom Serface" <tom.nospam@camaswood.com>
Newsgroups:
microsoft.public.vc.language
Date:
Thu, 28 Feb 2008 07:53:47 -0800
Message-ID:
<AD8BA010-58AB-473E-8FF7-FC24CDC71112@microsoft.com>
Alex,

I typically would assign a pointer to NULL when I delete it and then I can
check with that.

int *myInt = NULL;

....

if(myInt == NULL)
    myInt = new int[100];

....

if(myInt != NULL) {
    delete myInt[];
    myInt = NULL;
}

When something could be deleted from more than one place you can make this
easier by providing a function to "delete" the object or arrays or whatever
and set them to NULL there.

Tom

"Alex" <Alex@discussions.microsoft.com> wrote in message
news:6ADB4007-4A30-48FD-A8E5-200C51422BBA@microsoft.com...

Hi all,

Please find the below code snippet. There, I deleted memory in main()
function as well as destructor of TestPointer. How to find whether that
resource is already deleted or not? Can I achieve it by using smart
pointers...

#include "stdafx.h"

class TestPointer
{
private:
int* m_pInts;

public:
TestPointer():m_pInts(0){}
~TestPointer(){delete[] m_pInts;}
SetPointer(int* ptrInts){m_pInts = ptrInts;}
};

int main(int argc, char* argv[])
{
int* pints = new int[100];

TestPointer obj1, obj2, obj3;

obj1.SetPointer(pints);
obj2.SetPointer(pints);
obj3.SetPointer(pints);

//stmt...1
//........
//........
//stmt...n

delete[] pints;

return 0;
}

Thanks in advance.
--
Thanks & Regards,
Alex.

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