Re: How to delete pointers held inside a vector

"Tom Widmer [VC++ MVP]" <>
Mon, 18 Jun 2007 18:09:22 +0100
ColinG wrote:


I have a class named MC.

Header contains the following:

struct tCDV
  int intC
  long lngR;
  bool blnE;
  CString strC;
 tCDV* p_cDV;

const int BUFF_SIZE;

std::vector<tCDV*> m_cDV;

Why do you have a vector of pointers to objects. Why not just:

std::vector<tCDV> m_cDV;

tCDV meets the requirements for storage in a vector (it's copyable and

Unit contains the following:


   p_cDV = new tCDV[BUFF_SIZE];

You create an array of 32 tCDV objects here, but below you only access
the first one. Is this intentional? Are you sure you didn't mean:
p_cDV = new tCDV;

   p_cDV->intC = cc; //cc initialised elsewhere in program
   p_cDV->lngR = cr; //cr initialised elsewhere in program
   p_cDV->blnE = file.read_bool(); // file.read_bool() initialised elsewhere
in program
   p_cDV->strC = file.read_string(); // file.read_string() initialised
elsewhere in program


All the above works fine. My problem is that I receive memory leaks on
program exit and the debugger points to:

    p_cDV = new tCDV[BUFF_SIZE];

I attempted to iterate through the vector: m_cDV (via the destructor of
class MC), deleting the pointers p_cDV but to no avail.

You created them with new[], so you need to delete with delete[]:

delete[] m_cDV[i];

So, I scrapped the

iteration code.

Please can someone assist me in resolving this problem.

The best solution is not to use pointers at all (which will often give
faster as well as shorter code). The next best solution is to use either
a pointer container class, or a smart pointer class. That way you don't
have to manually delete the objects at all. See:


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