Re: How to revise a charactor in string?
"Vladimir Grigoriev" <vlad.moscow@mail.ru> ha scritto nel messaggio
news:eos8O9BZIHA.4208@TK2MSFTNGP04.phx.gbl...
I think that if you use an array then it is better for readability of the
code to use element array notation instead of pointer notation.
I.e.
c[count-1] = 'e';
I agree with you (in fact, in the code I posted above in this thread I used
the array syntax).
Moreover, at least the VS2008 C++ compiler, produces the same assembly code
for both the pointer form and the array syntax:
<disassembly>
*(buf + count - 1) = 'e';
00411F4E mov eax,dword ptr [ebp-70h]
00411F51 mov byte ptr [ebp+eax-65h],65h
buf[count - 1] = 'e';
00411F4E mov eax,dword ptr [ebp-70h]
00411F51 mov byte ptr [ebp+eax-65h],65h
</disassembly>
I recall that I was told that in C/C++, using pointers was faster than using
array syntax; but it seems that these quality compilers like Visual C++ can
optimize array syntax using pointers, so we can have the more readable array
syntax in source code, with the efficiency of pointer-based code.
Giovanni
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