Re: How to get address of iterator currently pointer to?

David Wilkinson <>
Wed, 08 Aug 2007 11:39:15 -0400
Jack wrote:

"Jack" <> ?????????g??????l??????s???D:Ob0Lusc2HHA.6128@TK2MSFTNGP02.phx.gbl...

Let's say I have an iterator "it"
std::string::iterator it;
char *__w64 startAddr = &it[0];
char *__w64 endAddr = startAddr + buf.size();
The start and end addresses tell me the start and end of file in memory

After it is incremented for a few times, I'd like to get the address of
the iterator currently pointing to?
The problem is if I compare "it" with another address, using the form
if (it <= endAddr)
      break the infinite loop

   if (it >= endAddr)
            break the loop

the compiler doesn't like it and throws C2678.
Does anyone know how to work around it?


You are never going to get anywhere if you keep mixing these old C ways
with the C++ standard library. Get a book!!!

AFAIK, iterators do not define operator [], unless they happen to be
implemented as pointers (which they may or may not be).

Also, unlike std::vector, std::string is not guaranteed to be stored in
contiguous memory (although it probably always is).

std::string = "12345";
std::string::iterator itBegin = str.begin();
std::string::iterator itEnd = str.end();

for (std::string::iterator it = itBegin; it != itEnd; ++it)
   // stuff

David Wilkinson
Visual C++ MVP

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