Re: What this line of code means?

From:

"Samant.Trupti@gmail.com" <Samant.Trupti@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Tue, 10 Jul 2007 23:20:56 -0700

Message-ID:

<1184134856.700322.253320@i13g2000prf.googlegroups.com>

On Jul 11, 11:07 am, Hooyoo <zhao_huy...@126.com> wrote:

On Jul 11, 12:28 pm, "Samant.Tru...@gmail.com"

<Samant.Tru...@gmail.com> wrote:

Hi all,

  I have some code that I am unable to understand. Can you please
help?

int _tmain(int argc, _TCHAR* argv[])
{
  // Initialize COM environment.
        ccLib::CCoInitialize CoInitialize(ccLib::CCoInitialize::eMTAModel);
...}

1. CCoInitialize is a class
    to invoke a object of class you write
    CCoInitialize cc;
2. CoInitialize is static function.
    to invoke static function you write scope resolution "::"

ccLib::CCoInitialize::CoInitialize(ccLib::CCoInitialize::eMTAModel);

when they have "space" instead of "::" what is that mean? What are
they trying to do?

Thanks
Trups

I think ccLib is a namespace, and that line means to instantiate
class CCoInitialize that is defined in namespace ccLib.- Hide quoted text -

- Show quoted text -

Thanks for your answer. Yes ccLib is a namespace. I still have a
question
CoInitialize(ccLib::CCoInitialize::eMTAModel); returns HRESLT so this
function should be
HRESULT result = CoInitialize(ccLib::CCoInitialize::eMTAModel);
and ccLib::CCoInitialize cclib; this should be instantiation
what do you mean when you combine both?
ccLib::CCoInitialize CoInitialize(ccLib::CCoInitialize::eMTAModel);
That space (CCoInitialize CoInitialize) I am confuse with.

Thanks