Re: circular function pointers declaration?

From:
benben <benhongh@yahoo.com.au>
Newsgroups:
comp.lang.c++
Date:
Thu, 27 Apr 2006 18:11:34 +1000
Message-ID:
<44507cb7$0$7600$afc38c87@news.optusnet.com.au>
Timothee Groleau wrote:

Hi,

Is it possible to declare a function pointer whose arguments is a pointer to
a function pointer of the same type? Something like:

=====
typedef unsigned long (*myFuncPtr) (myFuncPtr*);
=====


OPTION A
----------------------------------------------
Simply:

     typedef unsigned long (*myFuncPtr) (void*);

Just be careful to cast your pointers to void*.

OPTION B
----------------------------------------------
Abstract base class approach:

    class my_itf
    {
    public:
        virtual unsigned long
            operator()(my_itf& pnext) = 0;
    };

    template <unsigned long N>
        class my_itf_end: public my_itf
        {
        public:
            unsigned long operator()(my_itf&)
            {
                return N;
            }
        };

which can be used like:

    class A: public my_itf
    {
    public:
        unsigned long operator()(my_itf& next)
        {
            return next(my_itf_end<5>());
        }
    };

    int main()
    {
        A a;
        my_itf& f = a;

        f(f);
    }

Pick your poison :)

Regards,
Ben

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