Re: Multiply inherit from classes with conflicting function names

From:
"Maxim Yegorushkin" <maxim.yegorushkin@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
25 May 2006 09:33:22 -0400
Message-ID:
<1148455463.888436.308200@i40g2000cwc.googlegroups.com>
Adam wrote:

I have an unfortunate case where a single class wants to derive
from two
existing classes:

struct A { virtual long fun() = 0; };
struct B { virtual bool fun() = 0; };
struct Unfortunate : public A, public B { ??? };

Is it possible to fill in the ??? here with legal code?
I need two different function bodies; A::fun and B::fun do unrelated
things.


Yes, you need an intermediate class here.

struct A_tag {} const a_tag = {};
struct B_tag {} const b_tag = {};

// zero overhead shim
template<class derived>
struct A_shim : A
{
     long fun() { return static_cast<derived*>(this)->fun(a_tag); }
};

// virtual call overhead shim
struct B_shim : B
{
     bool fun() { this->fun(b_tag); }
     virtual bool fun(B_tag) = 0;
};

struct fortunate : A_shim<fortunate>, B_shim
{
     long fun(A_tag);
     bool fun(B_tag);
};

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