Re: Non-template class from a template base class with pure virtual methods

From:
Kai-Uwe Bux <jkherciueh@gmx.net>
Newsgroups:
comp.lang.c++
Date:
Sun, 25 Mar 2007 13:29:56 -0400
Message-ID:
<eu6bil$sh3$1@murdoch.acc.Virginia.EDU>
vilarneto@gmail.com wrote:

Hello everyone,

I'm facing a particular situation about template class derivation.
The subject is old -- deriving a non-template class from a template
base class -- but my problem is that the base class has a pure virtual
method. For instance:

template<class T>
class A {
public:
    virtual void method() = 0;
};

class B : public A<int> {
public:
    // neither of the following worked:
    // void method() { }


Actually, the above looks right and works for me. What error do you get?

    // void method<int>() { }
    // template<int> method() { }
};

int main(int argc, char *argv[]) {
    B b;
    return 0;
}

This is probably simple, but I couldn't figure out a way to implement
the derived method.

Also, I don't know if this matters, but I'd better stay apart from
compiler idiosyncrasies -- I'm searching for something portable, at
least between g++3.4.4 and VC7.

Does anybody have any hint about this?


Try the following with your compilers:

#include <iostream>

template<class T>
class A {
public:
    virtual void method() = 0;
};

class B : public A<int> {
public:
  void method() { std::cout << "hi!\n"; }
};

int main(int argc, char *argv[]) {
    B b;
    b.method();
    return 0;
}

Best

Kai-Uwe Bux

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