Re: Function pointer problem

From:

Branimir Maksimovic <bmaxa@hotmail.com>

Newsgroups:

comp.lang.c++

Date:

9 May 2007 13:12:41 -0700

Message-ID:

<1178741561.380962.267700@y5g2000hsa.googlegroups.com>

On May 9, 7:12 pm, Adrian <n...@bluedreamer.com> wrote:

Example A fails to compile with
exampleA.cpp: In member function 'void A::a() const':
exampleA:10: error: no matching function for call to 'A::b(const
std::string&) const'
exampleA:17: note: candidates are: virtual void (* A::b(const
std::string&))()const <near match>

Example B compiles fine.

Now I assume that the const is not binding to what I think it should
in the example A

Adding the typedef fixes this

Can anyone tell me what is going on

Adrian

+++++++++++++ Example A +++++++++++++++
#include <iostream>
#include <string>

class A
{
   public:
      void a() const
      {
         const std::string arg("test");
         void(*func_ptr)(void)=b(arg);
         if(func_ptr)
         {
         }
      };
      virtual ~A() throw();

      virtual void (*b(const std::string &str))(void) const=0;

Are you sure that this is not syntax error? This looks like try
to define pointer to function and declare pure virtual function
in the same time. This syntax works for me:

virtual void(* b(const std::string &str)const)(void)=0;

Greetings, Branimir.