Re: Calling a Private function using Virtual Instance

From:
Kai-Uwe Bux <jkherciueh@gmx.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 13 Mar 2008 11:17:00 -0400
Message-ID:
<frbghd$rut$1@aioe.org>
Pravin wrote:

Hi all,

please look at this code

"

class VirtualBase{

          public:
virtual int method1() = 0;
virtual int method2()=0;
virtual int method3()=0
};

class DerivedBase:public VirtualBase
{
        public:
int method1(){
return 2;
}
int method2(){
return 2;
}
       private:
int method3(){
return 2;
}
};

void main(){

DerivedBase ObjDerivedBase;
VirtualBase *ObjVirtualBase;

ObjVirtualBase = new DerivedBase;
cout<<"\nReturn:"<<ObjVirtualBase->method3();
}

"

Here..inspite of DerivedBase::method3() being private, i can still
call it using a pointer to VirtualBase after assigning a object of
DerivedBase.

I have difficulty understanding how this could be possible?


Access (public, private, protected) only relates to the static types. Since
*ObjVirtualBase is of static type VirtualBase, it allows you to access the
public member function method3. The dynamic type only determines which
implementation will be dispatched; it does not determine whether the member
function is accessible. See [11.6/1] for details.

Best

Kai-Uwe Bux

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