Re: should this work?

From:
Looney <hardy_melbourne@hotmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 8 Apr 2008 18:56:24 -0700 (PDT)
Message-ID:
<ffd86992-a5de-4afb-95de-85b2de92e4c9@e10g2000prf.googlegroups.com>
On Apr 9, 7:42 am, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

Puppet_Sock wrote:

So I've had to take over a project that used an old compiler.
May not be able to step up to a newer compiler because the
project uses a library that has equivalent of the following in it.

#include <iostream>
class A
{
public:
A();
virtual void tryit(long val) = 0;
};

class B: public A
{
public:
virtual void tryit(long val);
long m_val;
};

A::A()
{
tryit(17);


This is a call to a pure virtual function. The behaviour is U.

}

void B::tryit(long val)
{
m_val = val;
}

int main()
{
B myB;
std::cout << myB.m_val << std::endl;
}

I don't think this should work in a compliant compiler. When class A
tries to find tryit, it should not. I get a linker error in my more
recent
compiler.

But the old compiler I'm using for the project happily compiles and
links, and behaves as though the class A is finding the entry in
class B for the function tryit.

Am I missing something? This shouldn't work should it?


It should not.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask


It should not work as when A's constructor is executing it does not
have complete knowledge of it's VTable
as which functions have been overriden as the object construction has
not completed yet. So as a rule of thumb
never expect virtual calls inside constructor to call child class's
implementation.

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