Re: Derived class hiding a name

From:
Bart van Ingen Schenau <bart@ingen.ddns.info>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 22 May 2008 15:37:17 CST
Message-ID:
<1482981.s5NlutZXz8@ingen.ddns.info>
jordigh@gmail.com wrote:

The following code will not compile:

     class foo{};

     class A{
     public:
       void f(int a ){a++;};
     private:
       virtual void f(foo a) = 0;
     };

     class B : public A{
     private:

Put a
     using A::f;
here to make all overloads of f accessible to callers with a B object.

       virtual void f(foo a){};
     };

     int main(){
       B b;
       int a=0;
       b.f(a);
     }

The problem seems to be that all of my functions being named f are
somehow colliding with each other. It seems to me that the
call b.f(a) is unambiguosly pointing to A::f(int), but gcc disagrees.

I can fix this if I namespace the b.f(a) call, but that's a little
ugly. I can also fix it if I put a forwarding function inside B that
calls the proper function inside A, also a little ugly. I could also
mangle my functions' names, but I really feel that's the compiler's
job, not mine, especially since I think I already provided enough
context with a function signature. Also, I'd like to keep the
functions' names as they are, since they reflect an underlying
mathematical structure that really could use the same names.

If a using declaration should be enough to fix this, where should I
place? Or a better fix?


A using declaration is sufficient, if you place it in the definition of
class B, like I did above.

Thanks,
- Jordi G. H.


Bart v Ingen Schenau
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