Re: pure virtual function in template class

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 10 Jul 2008 13:28:40 -0400
Message-ID:
<g55gs8$76u$1@news.datemas.de>
Mike -- Email Ignored wrote:

On Thu, 10 Jul 2008 12:48:36 -0400, Victor Bazarov wrote:

Mike -- Email Ignored wrote:

On Thu, 10 Jul 2008 10:56:16 -0400, Victor Bazarov wrote:

[...]

It's the case when too much information actually hurt. What clacker
is telling you is that you can't have a template member declared
virtual (pure or not):

    class foo {
       template<class T> virtual void bar(T const&); // error
    };

, that's, all.

V

Then my working example is just dumb luck?

"Dumb luck"? I am not sure how that is applicable here. Your example
has no virtual functions that are member templates.


Then what is my function:

   virtual void doChild(TYP a)=0;// pure virtual member function


It's a pure virtual function, a member of the class template. Since it
is a member of a template, it is a template itself, but it's not a
member template. It's a template member. Confusing, isn't it?

Why is this ok?


Why wouldn't it be? Every instance of your class template gets its own
virtual function. For example, your BaseT<int> has

     virtual void BaseT<int>::doChild(int) = 0;

and it's pure, so any derived class has to override it if it wants to be
non-abstract (and your 'Child' provides it); and if you had some other
instance of your template, say, 'BaseT<std::vector<std::string> >', then
it would have

     virtual void BaseT<std::vector<std::string> >
                           ::doChild(std::vector<std::string> ) = 0;

which also has to be overridden in the derived class, should you want to
instantiate the derived class by itself (make it non-abstract).

Please feel free to ask more questions.

V
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