Re: Making a smart pointer which works with incomplete types

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
Sun, 07 Sep 2008 19:02:17 GMT
Message-ID:
<ZyVwk.340$nL5.225@read4.inet.fi>
Lance Diduck wrote:

There has been a long standing feature in C++ called "virtual
desstructor" that exacly solves this problem in this same way.i.e.
struct Incomplete{
virtual void foo()=0;
virtual ~Incomplete(){}
};
struct Complete:Incomplete{
void foo(){}
};
Incomplete * i=new Complete;
delete i;//does not require Complete type
That last line is resolved at runtime to be:
i->~Complete();
Complete::operator delete(dynamic_cast<void*>( i));

So I am unclear on why you may want to do this manually in a smart
pointer?


  You have a confusion here. A type is incomplete when it has only been
declared, but not defined. Consider this:

//---------------------------------------------------------------
class A; // Declaration. 'A' is an incomplete type.

A* getA(); // A function implemented somewhere else

int main()
{
    A* ptr = getA();

    delete ptr;
    // 'ptr' gets destroyed here, but 'A' is incomplete.
    // The compiler doesn't have a definition of A, and thus
    // can't call its destructor.
}
//---------------------------------------------------------------

  That example might seem artificial, but in fact it happens more often
than you would think. It's very typical in classes, like this:

//---------------------------------------------------------------
class SomeClass
{
    class A; // Declaration. Definition is in the .cc file.
    SmartPtr<A> ptr; // Dynamically allocated in the constructor

 public:
    SomeClass();
    // Initializes 'ptr' with a dynamically allocated instance of A
};
//---------------------------------------------------------------

  If SomeClass doesn't have a destructor implemented in a context where
'A' is complete, the smart pointer will have to delete the object given
to it based on the definition only.

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