Re: How to enforce a virtual fn is overloaded by derived class?

From:
Pavel Minaev <int19h@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 12 Apr 2009 21:53:32 CST
Message-ID:
<6154d8e0-8b21-4256-b71e-79aa3f9cfc6c@k19g2000prh.googlegroups.com>
On Apr 12, 2:48 am, "Chris Morley" <chris.mor...@lineone.net> wrote:

I need to enforce requirement that the programmer overloads a particular
virtual function in all derived classes.

i.e.
class base {
public:
     virtual void foo() {} // base has some handler

};

class deriv1 : public base {
void foo() {} // good overridden

};

class deriv2 : public base {

}; // bad, no overload so I want compiler to choke


You should use a pure virtual function with a definition for that
(which is, quite possibly, a feature that is unique to C++):

 class base {
 public:
      virtual void foo() = 0; // pure virtual - must be overridden;
body cannot be defined inline, though
 };

 void base::foo() { // definition which can be called non-virtually
(e.g. from derived classes)
   ...
 }

 class derived : public base {
 public:
      virtual void foo() {
        base::foo();
        ...
      }
 }

Even in this case, derived classes still do not _have_ to override foo
- but if they don't, they become abstract themselves.

class base_base abstract {


Note that "abstract" class modifier is non-standard C++ (it's a C++/
CLI extension). Furthermore, even in C++/CLI, it is not required in
this case.

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