Re: Passing a class to a pure virtual function (without templates)

From:
DerTopper@web.de
Newsgroups:
comp.lang.c++
Date:
Wed, 22 Apr 2009 05:04:46 -0700 (PDT)
Message-ID:
<ff14ce77-c5a1-4a53-87e9-ebd4393e6155@d14g2000yql.googlegroups.com>
captaincurk@googlemail.com schrieb:

Hello there,

I have the following problem:

// abstract base class
class A {
public:
  virtual void addItems() =0;
};

class B : public A {
public:
  virtual void addItems() {
    // here I need to instantiate objects of a given type
  }
}

In B's something() function, I need to fill an internal list with
objects of a specific type. I need some way to pass my classname to
the function. Naturally I would try

template <class InstantiationClass> virtual void addItems() {
  list.push_back(new InstantiationClass());
}

Unfortunately that does not work, because pure virtual template
functions obviously don't work. Now I could move the template up to
the class B, but that is not very useful, as in my main program I will
call addItems very often and with different classes as parameters


Huh? What parameters? addItems doesn't take any parameters?

. Is
there an easy way to do this?


If you really need a virtual method for adding some Items, but also
have a lot of different things to create, you won't get a around class
template. Remember that you'll need a vtable to make virtual methods
work, and you only get a different vtable for each class you define.

Your problem description reads very confusing. The method for adding
new items takes no parameters, which is a bit odd. Probably that is
the source of your problem. Try to write a short summary of what
addItems should do, and most probably you'll see your problem.

Regards,
Stuart

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