Re: switch statement to detect handling of ALL derived classes

From:
Stuart Golodetz <sgolodetz@NdOiSaPlA.pMiPpLeExA.ScEom>
Newsgroups:
comp.lang.c++
Date:
Mon, 03 Aug 2009 12:22:10 +0100
Message-ID:
<sq2dneCB6_3_VevXnZ2dnUVZ8iRi4p2d@pipex.net>
Hicham Mouline wrote:

"Ian Collins" <ian-news@hotmail.com> wrote in message
news:7dnt8mF2aibr6U5@mid.individual.net...

Hicham Mouline wrote:

"Ian Collins" <ian-news@hotmail.com> wrote in message
news:7dnoc8F2aibr6U4@mid.individual.net...

Hicham Mouline wrote:

Imagine we have an abstract base class ABC and derived classes D1, D2,
... Dn

I am being told a code pattern to "enforce" all cases are handled is
such:

enum ABCTypes { D1Tag, D2Tag, .... DnTag };

const ABC& base

ABCTypes t = base.getTag();
swich(t)
{
 case D1Tag:
 ...
 case DnTag:
}

without the default branch.

If you add a Dnplus1 derived class and its tag Dnplus1Tag in the enum
ABCTypes ,
all code patterns with the switch-case will generate an error if you
forget to handle the Dnplus1 case.

Eh?

1) Does the standard "require" handling all cases of the enum? Or does
it only say a conforming implementation should print a warning?

Neither.

g++ prints a warning when not all enum values are handled in the switch
case.
That is a choice made but that implementation then.

2) Are there opinions on this style? I don't like the use of the
getTag() method in the ABC class to facilitate this style.

It's horrible, why not just use virtual functions?

I also don't like it.... But I need to show an alternative.

Why?

The processing done in the switch case is not inherently related to the
ABC.
I'd rather not put that processing in a member virtual function of ABC,
but rather some external function that takes ABC
In that function, I could use

if (dynamic_cast<D1*>( base ))
   ///
if (dynamic_cast<D2*>( base ))
   ///
....
if (dynamic_cast<Dn*>( base ))
 ///
but with this, I can't even get a warning if I am missing Dnplus.

That's even worse.

Is there a different way of using the virtuality without writing member
virtual functions?

What's wrong with

struct ABC {
  virtual void doSomething() = 0;
};

struct D1 : ABC {
  void doSomething() { // does something }
};

...

base.doSomething();

All derived classes must provide doSomething(), so no case can be left out
by mistake.

--
Ian Collins


Because doSomething is not immediately relevant to ABC.
It's 3rd party code using my hierarchy that I provide for them.


Are you in search of something like the visitor pattern by any chance?

http://en.wikipedia.org/wiki/Visitor_pattern

Stu

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