Re: function calls

From:
Leigh Johnston <leigh@i42.co.uk>
Newsgroups:
comp.lang.c++
Date:
Tue, 01 Mar 2011 00:38:07 +0000
Message-ID:
<V_SdnTIe-K9tovHQnZ2dnUVZ7vSdnZ2d@giganews.com>
On 01/03/2011 00:17, Paul wrote:

"Leigh Johnston" <leigh@i42.co.uk> wrote in message
news:0ISdneozWv9VqvHQnZ2dnUVZ8ladnZ2d@giganews.com...

On 28/02/2011 23:54, Paul wrote:

"?? Tiib" <ootiib@hot.ee> wrote in message
news:fd3e7076-47da-40f3-aa05-9a0cf5aeb42d@p11g2000vbq.googlegroups.com...

On Feb 28, 9:45 pm, "Paul" <pchris...@yahoo.co.uk> wrote:

" Tiib" <oot...@hot.ee> wrote in message

news:7e2e42b3-2410-443a-95c2-46f262c8334b@n18g2000vbq.googlegroups.com...

On Feb 25, 11:07 am, "Paul" <pchris...@yahoo.co.uk> wrote:

Please let me know if you still do not understand and I will >

re-explain

again.


--Your code does not work. You can not overwrite object 'Dog dog;' in a
--way that Cat's destructor is called for it when that dog leaves
--scope ... Dog's destructor is called for it on all C++ compilers i
--could reach. What destructor will be called is pre-decided and set
--already compile time. So it seems that you do not understand yourself
--what you are talking about.

#include <iostream>
class Animal{};
class Dog: public Animal{};
class Cat: public Animal{};

int main()
{
Cat* p_cat = new Cat;
std::cout<< p_cat << std::endl;
delete p_cat;
Dog* p_dog = reinterpret_cast<Dog*>(p_cat);
p_dog = new Dog;
std::cout << p_dog;

}


--What does this code overwrite?
--Also ... most compilers optimize the two lines:

--Dog* p_dog = reinterpret_cast<Dog*>(p_cat);
--p_dog = new Dog;

--Into something like:

-- Dog* p_dog = new Dog;

It doesn't trully overwrite anything but its the closet example I can
give, using C++ code.

Here is some code that demonstrates a similar thing:

#include <iostream>
class Animal{public:
virtual void eat(){std::cout<< "Animal Eating"<< std::endl;}
virtual int getID()=0;
static int count;
};
class Dog: public Animal{
public:
void eat(){std::cout<< "Dog Eating"<< std::endl;}
int getID(){return 1;}
};
class Cat: public Animal{
public:
void eat(){std::cout<< "Cat Eating"<< std::endl;}
int getID(){return 0;}
};
int Animal::count =10;

Dog* overwriteCat(Animal* ptr){
delete ptr;
Dog* p = reinterpret_cast<Dog*>(ptr);
p = new Dog;
return p;
}

Cat* overwriteDog(Animal* ptr){
delete ptr;
Cat* p = reinterpret_cast<Cat*>(ptr);
p = new Cat;
return p;
}

void ordinary_function(Animal* obj){
Animal::count--;
std::cout<<"Address of obj: " <<obj << " ";
obj->eat();
if(obj->getID()){overwriteDog(obj);}
else {overwriteCat(obj);}
if(Animal::count){
ordinary_function(obj);
}
}

int main()
{
Cat* p_cat = new Cat;
Animal* p_anim = p_cat;

ordinary_function(p_cat);
}

You cannot do this type of recursion with a member function, a member
function belongs to the object with which its called.


In C++ a member function does not belong to a particular object; in
C++ a non-static member function is invoked on an object; in C++ a
member function is a member of a class not an object.


If its a member of the class its also a member of the object you
f*#"&i%$ moron.
If its a member of a class and not a member of an object it can only be
a static class member.

Please keep your ignorant, negative , spamming comments to yourself if
you have no reasoning to support your argument.


You have been reasoned with many times by many people; you prefer to
ignore reason; your behaviour is childish at best.

/Leigh

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