Re: Slicing with ?: operator - expected?

From:
"Paul" <pchristor@yahoo.co.uk>
Newsgroups:
comp.lang.c++
Date:
Thu, 7 Jul 2011 01:47:38 +0100
Message-ID:
<Pm7Rp.9$ux6.4@newsfe07.ams2>
"Victor Bazarov" <v.bazarov@comcast.invalid> wrote in message
news:iv1p6s$acb$1@dont-email.me...

Hello All,

Here is the code:

   class Foo {
   public:
      virtual void bar() const = 0;
   };

   #include <ostream>
   #include <iostream>

   class Foo1 : public Foo {
      void bar() const { std::cout << "Foo1::bar\n"; }
   };

   class Foo2 : public Foo {
      void bar() const { std::cout << "Foo2::bar\n"; }
   };

   void foo(const Foo* pFoo)
   {
      (pFoo ? *pFoo : Foo1()).bar(); // line 19 ************


What object is the argument pFoo pointing to?

   }

   void blah(const Foo& rFoo)
   {
      foo(&rFoo);

Is a temporary reference to a Foo on the call stack?
I think this is the case and there is no Foo2 object.

   }

   int main()
   {
      blah(Foo2());


What is the lifespam of the temporary?

   }

Line 19 is the line in question. Could you please interpret it for me? It
seems to skip the virtual function dispatch, and attempt to call the pure
function. The common type of *pFoo and Foo1() is 'class Foo', and the
compiler seems to resolve the 'bar' statically, without the use of virtual
function mechanism, as if there is an instance of class Foo /sliced/ from
both original objects. Is that supposed to happen? Standard chapter and
verse would be helpful.

To avoid a pure function call I can implement the base class' member
function 'bar'. The problem is that in that case I get the dynamic
dispatch I need (I expected Foo2.bar() to be called), I am getting the
base class. Is that what *should* happen?


Havent debugged it but maybe it has something to do with the lifespam of the
temporary. Have you tried it using a non temporary object?

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