Re: Multiple inheritance virtual abstract method disambiguation

From:
Gerhard Menzl <clcppm-poster@this.is.invalid>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 8 Aug 2011 11:58:12 CST
Message-ID:
<j1o2ot$5ja$1@news.datemas.de>
On 2011-08-07 21:08, xKubo@hotmail.com wrote:

Assume the ITest and ITest2 cannot be modified, and I would like to
implement them in one class, but differently for each interface, is it
possible in standard C++ ?


Yes. Like every other (except the halting) problem, this one can be
solved using an extra level of indirection.

struct ITest
{
    virtual void Close() = 0;
};

struct ITest2
{
    virtual void Close() = 0;
};

struct X : ITest, ITest2
{
///// something like this is probably incorrect
//// virtual void ITest::Close() {}
//// virtual void ITest2::Close() {}
};


struct XITest1 : ITest
{
    virtual void Close() { Close1(); }
    virtual void Close1() = 0;
};

struct XIText2 : ITest2
{
    virtual void Close() { Close2(); }
    virtual void Close2() = 0;
};

struct X : XITest1, XITest2
{
    virtual void Close1();
    virtual void Close2();
}

--
Gerhard Menzl

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