Re: Using printf in C++

From:
scott@slp53.sl.home (Scott Lurndal)
Newsgroups:
comp.lang.c++
Date:
23 May 2012 16:46:36 GMT
Message-ID:
<Mv8vr.50665$L45.14313@news.usenetserver.com>
Robert Wessel <robertwessel2@yahoo.com> writes:

On Wed, 23 May 2012 16:40:34 +0200, jacob navia <jacob@spamsink.net>
wrote:

In gcc you can declare a function "printf-like" if I remember
correctly.


Interesting. Any references? It wouldn't help much for us, since it
would obviously be a GCC extension, but I'd be curious to see how that
worked. Format strings are not always completely defined in one
place, or in what nominally C code, or defined with their parameters
in the same form as passed to *printf.


See the definitions for the log() and trace() methods below.

class c_logger {

    bool l_debug;

public:
    c_logger(bool d) { l_debug = d; }
    virtual ~c_logger(void) {};

    void log(const char *, ...)
            __attribute__((format(printf, 2, 3)));
    size_t trace(const char *, ...)
            __attribute__((format(printf, 2, 3)));

    virtual void log(const char *, va_list) = 0;
    virtual size_t trace(const char *, va_list) = 0;

    void set_tracing(bool d=false) { l_debug = d; }
    bool is_tracing(void) { return l_debug; }
};

$ info gcc -> C Extensions -> Function Attributes -> format

Note that you need to count the implicit 'this' argument in the format() attribute parameters

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