Re: Clone an object with an abstract base class
On 11/10/2014 22:46, Urs Thuermann wrote:
I want to clone an object through a pointer to its abstract base
class. Say I have the following classes
class B {
virtual void foo() = 0; // abstract base class
};
class D1 : public B {
virtual void foo();
};
class D2 : public B {
virtual void foo();
};
Then I can clone objects when I know the subclass of B
void f1(D1 *d1, D2 *d2) {
B *b1 = new D1(*d1);
B *b2 = new D2(*d2);
}
but not if I only have a pointer to the abstract base class
void f2(B *b) {
B *b1 = new B(*b); // error: cannot create a B
}
With GCC and -std=c++11 I can write
void f2(B *b) {
B *b1 = new auto(*b);
}
Is this the correct and preferred way in C++11?
In C++98 the only way I found is to add a pure virtual function
B *B::clone() const
and
B *D1::close() const { return new D1(*this); }
B *D2::close() const { return new D2(*this); }
and then call b->clone() instead of the new operator.
Is there a way to do this in C++98 without the need to add a new
function like clone() in each derived class?
urs
How about checking the type of the *b object first and creating that
type of object:
void f2(B *b) {
B *b1 = nullptr;
if( typeid(*b).name() == typeid(D1).name() )
b1 = new D1(*b1); // *b is type D1
else if( typeid(*b).name() == typeid(D2).name() )
b1 = new D2(*b1); // *b is type D2
}
and maybe also *b1 must be converted to its type like:
new D1( *((D1*)b1) )
?
Thats how I would do it propably :). At least a go-around. But there
might be better ways.
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